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Mariana [72]
3 years ago
7

Suppose that news spreads through a city of fixed size of 900000 people at a time rate proportional to the number of people who

have not heard the news.a. Formulate a differential equation and initial condition for y(t) , the number of people who have heard the news t days after it has happened.No one has heard the news at first, so y(0)=0.dy/dt = k ( what ) , where k is the proportionality constantb.) 8 days after a scandal in City Hall was reported, a poll showed that 100000 people have heard the news. Using this information and the differential equation, solve for the number of people who have heard the news after t days.y(t) = what
Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

The relation is ln(\frac{900000}{900000 - y(t)} ) = kt

Step-by-step explanation:

Here we have

\frac{dy(t)}{dt} =k(900000-y(t))

Integrating we get

-ln(900000 - y(t)) = kt + C

With initial condition y(0) = 0 we get

C =  -ln(900000)

Therefore,

ln(\frac{900000}{900000 - y(t)} ) = kt

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