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3 years ago

There are 140 legs on a planet zids have 5 legs and zods have 7 legs h=how many soulutions are there

1 answer:

8 0

Number of zids=x
number of zods=y
number of zid legs=5x
number of zod legs=7y

so
5x+7y=140
try to get it into slope intercept from so you can graph is (y=mx+b)
5x+7y=140
subtract 5x from both sides
7y=140-5x
divide both sides by 7
y=20-5/7x
y=-5/7x+20

plug in numbers for x and get numbers for y (you can only plug in multiples of 7 for x so that there are a whole number of zids and since you are counting, x and y must never be negative)

lets try 0 for x

y=-5/7(0)+20
y=20
so x=0 and y=20 is an answer (if you can have only one of that species)

lets try 7 for x
y=-5/7(7)+20
y=-5+20
y=15

so x=7 and y=15 is an answer

lets try 14 for x

y=-5/7(14)+20
y=-10+20
y=10

so x=14 and y=10 is another answer

lets try 21 for x
y=-5/7(21)+20
y=-15+20
y=5

so x=21 and y=5 is another answer

lets try 28 for x
y=-5/7(28)-20
y=-20+20
y=0

so x=28 and y=0 is an answer (if there can be only one of a species)

if we go further, then y will be negative so the answers are

(x,y)
(0,20)
(7,15)
(14,10)
(21,5)
(28,0)

if it is allowed that only one species exists then there are 5 possible answers
if both must exist simultaneously, then there are only 3 answers
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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

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3 years ago

According to your graphing calculator, what is the approximate solution to the trigonometric inequality cox(x)>-7/8 over the

stealth61 [152]

Answer:

0<=x0.7896

0<=x<0.9799

0<=x<0.9870

0<=x<1.2249

4 0

2 years ago

Erin is making fruit salad.For each bowl of fruit salad,she needs 2/3 cup of strawberries.How many cups will she use if she make

grigory [225]

She needs 18 times of 2/3 cup, this is

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5 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

lapo4ka [179]

The correct Option is (C) 5x(3x^2 + 4)

Explanation:
15x^3 + 20x

Take common terms out:
5x(3x^2 + 4) Which is option C.

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3 years ago

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Ilya [14]

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2 years ago