Answer:
Yes
Step-by-step explanation:
3 medium cars to 1 small car can be made into a fraction like this: or
. But you must be consistent if the denominator represents medium cars or small cars.
For this, I'm just going to make medium cars the numerator.
18 medium cars to 6 cars can be made into a fraction like this : .
When you divide both fractions in a calculator (or in your head), you will realize that they both are the same value (equivalent).
These ratios are equivalent.
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) (cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) (cumulative)
(d) (cumulative)
(e)
Step-by-step explanation:
vector AB(3-(-6); 5-7)
vector AB(9;-2)
AB= =
M is the midpoint of AB
we have B(-5;10) and M(1;7)
let A(x;y)
(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7
(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4
so : A(7;4)
the center of the circle is the midponit of the line joining both ends of the diameter
let A(x;y) be the other end
(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6
(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7
so the coordinates of the other end are (6; -7)
A,B and C are collinear such as AB=BC so b is the midpoint of AC
(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2
((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17
so x= 17 and y = -2