The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
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Answer:
Top box is +, left box is +, right box is -, bottom box is +
Step-by-step explanation:
Hopefully that makes sense lol
200+400=600 u just add 2 and 6 togather and u get 6 and then annd the two zeros on too it
Answer:
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.
Step-by-step explanation:
We are given the following information in the question:
The marginal price per pound (in dollars) is given by:
where x is the supply in pounds.
The coffee shop is willing to supply 9 pounds per week at a price of $7 per pound.
Thus, we are given that
P(9) = 7
Putting the values, we get,
Now, we have to find how many pounds it would be willing to supply at a price of $4 per pound.
P(x) = 4
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.
Answer:
Factor x2+5x+6x2+5x+6 using the AC method.
(x+2)(x+3)
