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3 years ago

13

Sam and John live on the same street. John is 1 year older then twice Sam’s age. When you sum their ages you get37.How old are e

ach of them

2 answers:

Lana71 [14]3 years ago

7 0

Answer:

15

Step-by-step explanation:

icang [17]3 years ago

7 0

Answer:

12 and 25

Step-by-step explanation:

2x+1+x=3x+1

37-1=36

36/3=12

12*2+1=25 and 12

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If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate <em>y'</em> terms: $-6x^2=2yy'+y'$
[Algebra] Factor <em>y'</em>: $-6x^2=y'(2y+1)$
[Algebra] Isolate <em>y'</em>: $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

<u>Step 3: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute <em>y'</em>: $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

<u>Step 4: Find Slope at Given Point</u>

[Algebra] Substitute in <em>x</em> and <em>y</em>: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

2 years ago

What is the measure of the missing angle?<br><br> 76<br> 166<br> 86<br> 156

BabaBlast [244]

Answer:

156

Step-by-step explanation:

It the whole line’s angle measure would be 180 degrees. If you subtract 24 from 180 You get 156.

Please give me Brainly answer.

5 0

2 years ago

Read 2 more answers

Can someone help me for this question please? I just keep getting wrong answer! Pls someone explain to me step by step! ASAP!!!

Kobotan [32]

Answer:

84 feet

Step-by-step explanation:

This problem involves several steps. The first step is to realize that the given figure does not show the required number of vertical stringers. It shows 5, but there will be 7 of them. The given diagram is helpful in that it shows a vertical stringer on the centerline of the arches.

The second step is to write a function that will tell you how long the stringer will be. I find it convenient to write the equation for an arch shape such as this using the parent function h(x) = 1-x^2. This parent function gives an arch of height 1 and width 1 from center (a total width of 2). You want an arch that is 16 ft high and 40 ft wide (one side from center), so you must scale this parent function both horizontally (by 40) and vertically (by 16). It becomes ...

H(x) = 16(1 -(x/40)^2)

The taller arch is twice this height, so the length of a vertical stringer at position x is

vertical length = 2H(x) -H(x) = H(x)

That is, the function H(x) we defined can be used to find the length of the stringers.

The third step is to find the stringer lengths. It can save some energy if you realize that the problem is symmetrical, so that the stringer at x=-30 is the same length as the one at x=30. We need to find stringer lengths every 10 feet from -40 feet to +40 feet. Of course, the ones at ±40 feet are zero length, because that is where the two arches meet.

H(-30) = 16(1 -(3/4)^2) = 7

H(-20) = 16(1 -(1/2)^2) = 12

H(-10) = 16(1 -(1/4)^2) = 15

H(0) = 16

Then the fourth step is to add up the stringer lengths, rounding the result as required.

7 +12 +15 +16 +15 +12 +7 = 16 + 2(34) = 84 . . . . feet (no rounding needed)

Finally, you need to answer the question asked:

The sum of vertical stringer lengths is 84 feet.

5 0

2 years ago

Find the measure of each exterior angle of a regular polygon in which the sum

Basile [38]

Each exterior angle is 11.25°

8 0

3 years ago

The length of a rectangular football field, including both end zones, is 120 yards. The area of the field is 57,600 square feet.

egoroff_w [7]

Answer:

3a.False,the width is 53.33 yards

3b.true, the Length is 120 yards=360 feet

3c.True, width of the field is 160 feet.

3d. True,rea of the field is 6,400 square yards.

Step-by-step explanation:

Hello , I think I can help you with this

to solve this you must know the equivalence between feet and yard, which is

3 feet = 1 yard

Also, the area of a rectangle is the product of its length by its width

Area=length *width

Step 1

convert 120 yards into feet using a rule of three

3 feet = 1 yard

x feet= 120 yards

3/1=x/120

x=(120*3)/1

x=360 feet

so

120 yards= 360 feet

Step 2

isolate the width from the area´s equation to find out it.

Area=57600 square feet

length=360 feet

Area=length *width

width=Area/length

Width=57600 square feet/360 feet

Width=160 feet

Step 3

convert 160 feet into yards

1 yard= 3 feet

x yard= 160 feet

1/3=x/160

x=(1*160)/3

x=53.33 yards

width=53.33 yards

the area is (square yards)

Area=120 yards*53.33 yards

Area=6400 square yards

Step 4

Answer the questions.

3a.False,the width is 53.33 yards

3b.true, the Length is 120 yards=360 feet

3c.True, width of the field is 160 feet.

3d. True,rea of the field is 6,400 square yards.

Have a nice day.

7 0

2 years ago