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3 years ago

A trapezoid has bases of lengths 13 cm and 17 cm. The

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

135 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(a + b)

where h is the height and a, b the parallel bases

Here h = 9, a = 13 and b = 17 , thus

A = $\frac{1}{2}$ × 9 × (13 + 17)

= 0.5 × 9 × 30

= 135 cm²

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$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

We have given that the coordinates of the end point G and H are ( -6,5) and ( 2, -7 )

$\bold{\underline{To \: Find :- }}$

We have to find the length of GH

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

According to the distance formula, we get :- 

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

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