Can i get some help please

What is the difference between slope intercept and point slope form?

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Point slope form and slope-intercept form are both ways of expressing the equation of a straight line. Point slope form emphasizes the slope and ANY point on the line. Slope intercept form just shows the slope and the y-intercept of a line

3 0

1 year ago

Choose the correct solution and graph for the inequality.

kupik [55]

Answer:

The first one..

Step-by-step explanation:

4 0

2 years ago

H(x) = x3 + 7<br> Determine whether the function is one-to-one.

zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

passes the vertical line test to make sure it is indeed a function, and

also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

$h\left(x\right)\:=\:x^3\:+\:7$

Have a look at the attached graph.

The red portion represents the graph of the function $h\left(x\right)\:=\:x^3\:+\:7$ .

The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is indeed a function.

The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0

3 years ago

Is the relation a function?<br><br> Select Yes or No for each relation.

Lina20 [59]

Hello! There are a few things that determine whether or not something is a function. In this case, to determine whether a relation is a function, we look at the domains, which are the x-coordinates, the first number of the pair. If the number occurs in the x-coordinate for more than one pair in a relation, then it's not a function. If a number only occurs as an x-coordinate once in the relation, then it's a function. In other words, they each have only one y-coordinate in the relation. For this question, the first, second, and third relations are functions. The fourth one is not a function, because the 3 has more than one y-coordinate, so it occurs as an x-coordinate more than once. Here are the answers easier to read.

1st : yes
2nd: yes
3rd: yes
4th: no

3 0

3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago