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vazorg [7]
3 years ago
14

Ross calculated the missing side length of one of these triangles using the Pythagorean Theorem. Which triangle was it? Four tri

angles E, F, G, H are shown from left to right. Triangle E has two sides labeled 2 each, and the included acute angle is shown. Triangle F has one side labeled as 2 and the other as 3, and the included right angle is shown. Triangle G has one side labeled as 4 and the other as 2, and the included obtuse angle is shown. Triangle H has one side labeled as 6 and the other as 7, and the included acute angle is shown. E F G H Question 4(Multiple Choice Worth 5 points)
Mathematics
2 answers:
vesna_86 [32]3 years ago
6 0
I need to see the triangles to answer this properly

Korolek [52]3 years ago
6 0

the answer is triangle f


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What are potential roots of p(x) = x4 + 22x2 – 16x – 12
kow [346]
Simplify <span>22\times 2<span>22×2</span></span> to <span>44<span>44</span></span>
<span><span>{x}^{4}+44-16x-12<span><span>x<span><span>​4</span><span>​​</span></span></span>+44−16x−12</span></span>Collect like terms
<span><span>{x}^{4}+(44-12)-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+(44−12)−16x</span></span> Simplify</span><span><span>{x}^{4}+32-16x<span><span>x<span><span>​4</span><span>​​</span></span></span>+32−16x</span></span><span>
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8 0
3 years ago
Read 2 more answers
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
3 years ago
What is a relation and what makes it different from a function? How can you determine the domain and range of a function?
Misha Larkins [42]

Answer:

Note that both relations and functions have domains and ranges. The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

6 0
3 years ago
last week rafael drove m miles. this week he drove 153 miles. using m, write an expression for the total number of miles he drov
zzz [600]

The expression for the total number of miles he drove in the two weeks is m + 153

<h3>How to determine the expression for the total number of miles he drove in the two weeks?</h3>

The given parameters are

Last week = m miles

This week = 153 miles

The expression for the total number of miles he drove in the two weeks is

Expression = Last week + This week

This gives

Expression = m + 153

Hence, the expression for the total number of miles he drove in the two weeks is m + 153

Read more about expressions at

brainly.com/question/723406

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5 0
2 years ago
If x = -6, which inequality is true?
Sveta_85 [38]

Answer:

A

Step-by-step explanation:

-5 - 3(-6) > 10

-5 - -18 > 10

-5 + 18 > 10

13 > 10

3 0
3 years ago
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