Answer:
4/6
mark me brainliest please
2+4z-18
change it so it's an equation
2+4z-18=0
then get 4z alone on one side by subtracting 4z from both sides
2-18=-4z
-16= -4z
divide both sides by -4
a negative divided by a negative becomes positive
4 =z
plug it in
2+4(4)-18
4x4 is 16
2+16-18=0
0=0
the same can be done for the second one 2+k-8
make it 2+k-8=0
move the k to get it alone so subtract k from both sides
2-8=-1k
-6 = -1K
you can divide by K to make K=6
plug in 2+6-8=0
0=0
80
adding up the numbers 30,20,5,25
maybe im wrong but i hope it helps...
Answer:
15 dimes and 14 quarters.
Step-by-step explanation:
Let q represent number of quarters and d represent number of dimes.
We have been given that a collection of dimes and quarters contains 29 coins. We can represent this information in an equation as:
We know each dime is worth $0.10 and each quarter is worth $0.25.
We are also told that the total value of coins is $5. We can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, there are 15 dimes in the collection.
Upon substituting in equation (1), we will get:
Therefore, there are 14 quarters in the collection.
Answer:
Step-by-step explanation:
Put the square roots together
4*5 * sqrt(14z^2 * 21z^3)
4*5 * sqrt(2*7 * z^2 * 3*7 z^2 * z)
The rule is to remove the perfect square from under the square root sign, you take 1 member of the perfect square out of the root sign, and throw the other one away. If there are an odd number of factors under the root sign, leave one of them alone.
4*5 * 7 z * z sqrt(2 * 3 * z)
140 z^2 * sqrt(6z)
