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3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

2 answers:

Phoenix [80]3 years ago

6 0

Answer:

Step-by-step explanation:

ƒ(x) = 3x² – 2

g(x) = 4x + 2

1. Add the functions

By definition,

(ƒ + g)(x) = ƒ(x) + g(x)

3x² - 2

+ 4x + 2

3x² + 4x

(ƒ + g)(x) = 3x² + 4x

2. Evaluate (ƒ + g)(2)

(ƒ + g)(2) = 3(2)² + 4(2) = 3(4) + 8 = 12 + 8 = 20

Alexxx [7]3 years ago

4 0

Answer:

$\displaystyle 20 = (f + g)(2)$

Step-by-step explanation:

$\displaystyle [4(2) + 2] + [3(2)^2 - 2] = [8 + 2] + [3(4) - 2] = 10 + [12 - 2] = 10 + 10 = 20$

I am joyous to assist you anytime.

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40 points, please help with all of them

Kitty [74]

Answer:

$\large\boxed{Q1.\ \text{2 times greater}}\\\\\boxed{Q2.\ J. 3}\\\\\boxed{Q3.\ B. -\dfrac{4}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Q1.

We have the equation of a line p in the standard form

$4x-3y=7$

Convert to the slope-intercept form:

$4x-3y=7$ subtract 3x from both sides

$-3y=-4x+7$ divide both sides by (-3)

$y=\dfrac{4}{3}x-\dfrac{7}{3}$

The slope $m_1=\dfrac{4}{3}$

From the table we have the points (4, 3) and (7, 5). Calculate the slope of line q:

$m_2=\dfrac{5-3}{7-4}=\dfrac{2}{3}$

Divide the slope of p by the slope of q:

$\dfrac{4}{3}:\dfrac{2}{3}=\dfrac{4}{3}\cdot\dfrac{3}{2}=2$

Q2.

Parallel line have the same slope. Therefore, if we have the equation of the line in the slope-intercept form, then we have the slope:

$y=3x+2\to m=3$

Q3.

Parallel line have the same slope.

Calculate the slope from given points (-11, 5) and (-6, 1):

$y=\dfrac{1-5}{-6-(-11)}=\dfrac{-4}{-6+11}=\dfrac{-4}{5}=-\dfrac{4}{5}$

6 0

3 years ago

Help me with questions 8 and 9 for 20 POINTS!!!!!!

rewona [7]

Answer:

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Step-by-step explanation:

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3 years ago

2 Construct a rational function that will help solve the problem. Then, use a calculator to answer the question.

vaieri [72.5K]

Answer:

Dimension of box:-

Side of square base = 10 in

Height of box = 5 in

Minimum Surface area, S = 300 in²

Step-by-step explanation:

An open box with a square base is to have a volume of 500 cubic inches.

Let side of the base be x and height of the box is y

Volume of box = area of base × height

$500=x^2y$

Therefore, $y=\dfrac{500}{x^2}$

It is open box. The surface area of box, S .

$S=x^2+4xy$

Put $y=\dfrac{500}{x^2}$

$S(x)=x^2+\dfrac{2000}{x}$

This would be rational function of surface area.

For maximum/minimum to differentiate S(x)

$S'(x)=2x-\dfrac{2000}{x^2}$

For critical point, S'(x)=0

$2x-\dfrac{2000}{x^2}=0$

$x^3=1000$

$x=10$

Put x = 10 into $y=\dfrac{500}{x^2}$

y = 5

Double derivative of S(x)

$S''(x)=2+\dfrac{4000}{x^3}$ at x = 10

$S''(10) > 0$

Therefore, Surface is minimum at x = 10 inches

Minimum Surface area, S = 300 in²

7 0

3 years ago

Can someone help me? In this net, the two triangles are right triangles. All quadrilaterals are rectangles. What is its surface

Nikitich [7]

Answer:

Net Area = 168

Step-by-step explanation:

See attachment for complete question

I'll make reference to the attachment, when needed.

The shapes that make up the net are labelled 1 to 5.

So, to calculate the surface area of the net, we simply calculate the surface area of each label.

Label 1: Rectangle

Area = Length * Width

Area = 10 * 5

Area = 50

Label 2: Rectangle

Area = Length * Width

Area = 8 * 5

Area = 40

Label 3: Rectangle

Area = Length * Width

Area = 6 * 5

Area = 30

Label 4: Triangle

Area = ½Base * Height

Base = 6 and Height = 8

So:

Area = ½ * 6 * 8

Area = 24

Label 5: Triangle

Area = ½Base * Height

Base = 6 and Height = 8

So:

Area = ½ * 6 * 8

Area = 24

So, the net area is the summation of the calculated areas of label 1 to 5

Net Area = 50 + 40 + 30 + 24 + 24

Net Area = 168

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3 years ago

Using the picture attached, find EG

Anon25 [30]

Answer:

Step-by-step explanation:

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3 years ago

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