The answer is 2, just follow the order of operations
Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
Answer:
Range is y > 0
Step-by-step explanation:
We need to find the range of y = e^4x
The range is defined as a set of values of dependent variable for which the function is defined.
The exponential function of form c. n^x + k has range f(x) > k
in the given function y = e^4x ,k =0
so Range is y > 0
35% of 98 is 34.3
Change the percentage (35) into a decimal by dividing over 100:
35 / 100 = 0.3
Multiply the decimal and 98:
0.35 × 98 = 34.3
