Answer:
54 sq units
Step-by-step explanation:
The triangle at the top (FAB) has a base of 10 and a height of 3. Area of triangle is 1/2bh so 1/2(10 * 3) = 1/2 * 30 = 15 sq units
If you cut off the triangle you have a trapezoid, EBCD. A trapezoid is (b1 + b2)/2 * h, so (6 + 7)/2 * 6 = 13/2 * 6 = 6.5 * 6 = 39 sq units
Add them together: 15 + 39 = 54 sq units
Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to

we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone

substitute

step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
we have


substitute


step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
75000. one hundread thousand more would be 100,000 more that what is given making it 175,000
The puppy weighs 15.4 pounds, 40% of 11 is 4.4 so add that to the wight and its 15.4