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astra-53 [7]
4 years ago
10

Kevin ran 4 miles more than steve ran. the sum of their distance is 26 miles. how far did steve run? the domain of the solution

is (0, 4, 11, 22)
a. define your variable
b.Write algebraic expressions for the distances each person ran.
c.Write an equation that can help you solve the problem.
d.Solve the equation.
e.Check your answer.

the answer is 11 i think but i need you to do a through e
Mathematics
1 answer:
Bond [772]4 years ago
8 0

A I think beacuse it Kevin ran more but Steve didn’t run more or it doesn’t say you have to make it your own

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In your   "<span>^25Log27=a , then ^3log5," your " ^ " has been twice misplaced.  The symbol " ^ " always goes between your base (on the left) and your exponent (on the right."  Would you please go back to the original question and ensure that you have copied this problem exactly as it was given.</span>
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Explain how u can decide where to place the first digit of the answer for 6,139 / 153
storchak [24]

Answer:

The first digit would go in the tens place.

Step-by-step explanation:

First we estimate the approximate numbers. For 6130 we estimate 6000 and for 153 we estimate almost 150.

So dividing 6000 by 150 would give 40 .

The four would go in the ten's place .

Now check by dividing

         40.1     So the answer is correct. The quotient is 40.12.

153\sqrt{6139}

<u>       612</u>

           190

<u>            153</u>

<u>              37 </u>

The first digit would go in the tens place.

The answer is justified. We can easily decide where to place the first digit.

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4 years ago
What is the answer <br> simplify 2(5x+3)-2(2x-3)
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The table of values shows the number of touchdown passes that a quarterback threw in each of his first five football games of th
kvv77 [185]
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Setler79 [48]

Answer:  \bold{a)\quad x=\dfrac{35}{3}\qquad RS=13\dfrac{1}{3}\qquad ST=7\dfrac{2}{3}}

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                c)    x = 7          RS = 6               ST = 11

<u>Step-by-step explanation:</u>

Use the Segment Addition Postulate: RS + ST = RT

a) (2x - 10) + (x - 4) = 21

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Use the same formula to solve for b and c

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