1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonbull [250]
3 years ago
11

The Gaineys and the Arnolds are saving money for a trip to Utah to go snowboarding. The Arnolds are going to save a nickel on th

e first day of the month and then double the amount each day for a month. The Gaineys are going to start their savings by saving
$10
on the first day and then
$10
each day of the month.

Part A: Write a recursive and explicit formula for each option.
Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Write a recursive and explicit formula for each option.

  • The Arnolds

Save a nickel on the first day of the month and then double the amount each day for a month

=> a1 =0.05

=> a2 = a1* 2 = 0.05*2

=> a3 = a2*2 = a1* 2*2

..............................................

=>recursive an = a_{n-1} *2

=> explicit an = 0.05*2^{n-1}

  • The Gaineys

Start their savings by saving  $10  on the first day and then  $10  each day of the month

=> a1 = 10

=> a2 = a1 + 10 = 20

=> a3 = a2 +10 = 20 +10 =30

........................................................

=> recursive an = a_{n-1} +10

=> explicit an = 10 + 10( n-1)

Hope it will find you well.

You might be interested in
Need help ASAP
joja [24]

Part (1) : The solution is 729

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is 3^{2} \cdot3^{4}

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$, we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

3^{2} \cdot3^{4}=3^6=729

Thus, the simplified value of the expression is 729

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$, we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

\frac{1}{2^4x^8}

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$, we have,

\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}

Adding the powers, we get,

\frac{2x^{2}y^{-1}z^{-7}}{3}

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$, we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0
4 years ago
what is the mean of the set : 95,45,37,82,90,100,91,78,67,84,85,85,82,91,93,92,76,84,100,59,92,77,68,88​
zmey [24]

Answer:

The mean is 80.875

Step-by-step explanation:

8 0
3 years ago
Sadie computes the perimeter of a rectangle by adding the length, l, and width, w, and doubling this sum. Eric computes the peri
elena-s [515]
I have this same problem
6 0
3 years ago
1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff
Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If  A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that  f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0
4 years ago
The Red Robins are facing off against the Aliens in fantasy football. The Red Robins scored 393939 points this week. The Aliens
Inessa05 [86]

Answer:

25 points hbn nrnrrfkkkkkllm

jjj

6 0
3 years ago
Other questions:
  • Plot and connect the points A(6,-7), B(1,-7), C(1,-4), D(3,-2), E(7,-2), F(7,-4), and find the length of DE
    15·1 answer
  • The price of an item yesterday was $140. Today, the price fell to $63. Find the percentage decrease.
    8·2 answers
  • Convert 5 to the -3 power to a fraction
    5·1 answer
  • What is the exact value
    8·1 answer
  • The floor of the commons room at King Middle School is in the shape of a square with side lengths of x^2 y^3 feet. New tile is g
    8·1 answer
  • An item has a listed price of 90$. If the sales tax rate is 6% how much is the sales tax (in dollars)?
    5·1 answer
  • Suppose you cut a small square from a square of fabric as shown in the diagram. Write
    5·1 answer
  • Find m BAD. DAC=23 DC=7 BD=7
    11·2 answers
  • Find the factorization of x2 = 5x + 4.
    9·1 answer
  • Write 1.0315x10^6 in standard form
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!