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3 years ago

Simplify the expression completely.

Mathematics

2 answers:

JulsSmile [24]3 years ago

8 0

i have now attached the picture but it can be wrong!

ivolga24 [154]3 years ago

6 0

You can’t simplify it any further. 288 1/4 is already simplified.

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A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0

3 years ago

Graph y=x+1/x² and y=1/x for positive values of x.

AlekseyPX

Answer:

Graphic is showed in the figure below

Step-by-step explanation:

To graph the equations given, let's do a table for positive values of x, and, by replacing it in the equation, let's calculate the value of y. Knowing the coordinate points (x,y) we can build the graphic.

1 2 1

2 2.25 0.2

3 3.11 0.33

4 4.06 0.25

When x->0 both equations -> ∞, because lim(1/x) x->0 = ∞

The graphic is showed below. In red there is y = 1 + 1/x² and in blue y = 1/x

6 0

3 years ago

Find the exponential function that passes through the points (2,80) and (5,5120)

juin [17]

Answer:

y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

y = a·b^x

you can find the values of 'a' and 'b' as follows.

Substitute the given points:

y1 = a·b^(x1)

y2 = a·b^(x1)

Divide the second equation by the first:

y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

(y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

a = y1/(b^(x1))

In summary:

b = (y2/y1)^(1/(x2 -x1))
a = y1·b^(-x1)

For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

b = (5120/80)^(1/(5-2)) = ∛64 = 4

a = 80·4^(-2) = 80/16 = 5

The exponential function is ...

y = 5·4^x

3 0

3 years ago

HOW can you use bar diagrams to compare quantities in real-world situations

Vsevolod [243]

An example would be money! Money is a real life situation

3 0

3 years ago

Which input value produces the same output value for the two functions on the graph?

xeze [42]

X = 4 will give you the same output no matter what graph you are using.

8 0

3 years ago

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