So last week Paul worked 2.5x this week's hours, so he worked a total of 2.5x15= 37.5 hours last week.
6 x 8 = 48, the answer is 8, just divide 48 by 6.
Micheal answered 3 wrong.
Nythia answered 4 wrong.
Raul answered 1 wrong.
Tonya answered 7 wrong.
The other student lost 36 points.
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer: The answer is v=25.1 cm³
Step-by-step explanation:
b=4
h= 2
r= 4/2 r =2 radius is half of the diameter
V=πr²h
v= π(2)²2
v= 25.132741228718
v=25.1 cm³
