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Hitman42 [59]
4 years ago
14

Miss Ortega is purchasing 3.4 pounds of trail mix that cost 4.25 per pound how much change will Miss Ortega receive if she gives

the cashier $20
Mathematics
2 answers:
Elena-2011 [213]4 years ago
3 0

Answer:

$5.55

Step-by-step explanation:

4.25 * 3.4 = $14.45

20 - 14.45 = $5.55

marshall27 [118]4 years ago
3 0

First, find the total cost.

3.4 pounds x $4.25/pound = $14.45 total

Next, subtract the total cost from the amount she pays (we are assuming there is no tax in the question).

$20 - $14.45 = $5.55

So, she will receive $5.55 in change!

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A map has a scale of 1 : 20,000. The real-life distance between two schools is 8 km. What is the distance between the two school
levacccp [35]

Answer:

  40 cm

Step-by-step explanation:

  1 km = 10^5 cm, so 8 km = 8×10^5 cm

The map distance is 1/20,000 = 5×10^-5 of the real distance, so the map distance is ...

  (5×10^-5)(8×10^5 cm) = 40 cm

3 0
4 years ago
What are all the fractions are equivalent to 4/12
GarryVolchara [31]
The answers are 1/3, 2/6, 3/9, 4/12
5 0
3 years ago
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
AfilCa [17]
Given a solution y_1(x)=x^4, we can attempt to find another via reduction of order of the form y_2(x)=x^4v(x). This has derivatives

{y_2}'=4x^3v+x^4v'
{y_2}''=12x^2v+8x^3v'+x^4v''

Substituting into the ODE yields

x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0
x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0
x^6v''+x^5v'=0

Now letting u(x)=v'(x), so that u'(x)=v''(x), you end up with the ODE linear in u

x^6u'+x^5u=0

Assuming x\neq0 (which is reasonable, since x=0 is a singular point), you can divide through by x^5 and end up with

xu'+u=(xu)'=0

and integrating both sides with respect to x gives

xu=C_1\implies u=\dfrac{C_1}x

Back-substitute to solve for v:

v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2

and again to solve for y:

y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2
\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), t=\ln x. You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.
6 0
3 years ago
−4x+7y+5=0<br> x−3y=−5<br> ​ <br><br> How many solutions does the system have?
xeze [42]

   

Solution:  

Using Substitution Method:

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

get the value of x from Equation 2

x=3y-5     (Equation 3)  

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

-12y+7y=-5-20

-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore,   [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20     (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5    

-4x+12y=20    

+    -     = -   (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5  

Substituting y’s value is Equation 1

-4x+7(5)=-5

-4x+35=-5

-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0
3 years ago
Kevin bought 2 pieces of gum and 3 pieces of candy for $3.25. Jordan bought 4 pieces of gum and 1 candy bar for $2.75 at the sam
jenyasd209 [6]
G=gum c=candy 2g+3c=3.25 4g+c=2.75 c=2.75-4g 2g+3(2.75-4g)=3.25 2g+8.25-12g=3.25 -10g=5.00 g=0.50 c=2.75-4(.50) c= 2.75-2.00 c=0.75
6 0
3 years ago
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