Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
You need x 20 to get to 10000, so do the same with 150 and get 3000, so it is 3000/10000
194 in radical form is just √194. I don't believe any square roots go into it. Hope that helps. :)
( 732,178 + 167 ) = 899,178
899,178 - 542,137 = *357,041 that's the last result.
