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Nataly [62]
3 years ago
12

C=5/9(F-32) solve for F

Mathematics
1 answer:
mina [271]3 years ago
7 0
<span>F= 9/5 C + 32
      or
</span><span>F= 9/5(C+32)
</span>                          Hoped this helped:)
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What are the roots of the polynomial equation x^2+8x-48=0
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<span> Given polynomial x^2+8x-48 = 0</span>

<span>x^2+12x-4x-48 = 0</span>

<span>x(x+12)-4(x+12) = 0</span>

<span>(x+12)(x-4) = 0</span>

<span>x+12 = 0</span>

Subtract 12 from each side.

<span>x+12-12 = 0-12</span>

<span>x = -12</span>

<span>and x-4 = 0</span>

Add 4 to each side.

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4 0
3 years ago
Eight more than twice a number is equal to ten less than five times the number. Let n represent the number. Write an equation th
solniwko [45]
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3 years ago
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Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

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2 years ago
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Answer:

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3 years ago
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Answer:

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