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3 years ago

Are the lines below parallel, perpendicular, or neither?

Mathematics

2 answers:

I am Lyosha [343]3 years ago

8 0

Answer:

Neither

Step-by-step explanation:

<u>Given lines</u>

2y=3x-4 ⇒ y = 3/2x - 4
y= 2/3x - 3

The lines have different slope so they intersect but they are not perpendicular as perpendicular lines have negative reciprocal slopes

So the answer choice is neither

levacccp [35]3 years ago

5 0

Answer:

<h2>Neither </h2><h2></h2>

2y = 3x - 4

y = 2/3x - 3

Step-by-step explanation:

Parallel means the lines never cross. These two lines cross. Perpendicular means they cross and form a 90° angle.

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julsineya [31]

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Step-by-step explanation:

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3 years ago

Natalie earns $15 per hour. The store offers her a raise-a 4% increase per hour. After the raise, how much will Natalie make per

erastovalidia [21]

Answer:

15,6

Step-by-step explanation:

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3 years ago

- Trisha is making flags with 40 5/16 yards of fabric. If each flag requires 3 1/8 yards, how many flags can she make?

Westkost [7]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Solve to find x <br> log (3x+5) to base 5= 2log (1-3x) to base 25

Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

$\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x) }$

we can write 25 as 5²

$\mathsf{ \implies log_{5}(3x + 5) = 2 \: log_{ {5}^{2} }(1 - 3x) }$

we know that the reciprocal of the exponents of the bases are multiplied to the log

$\mathsf{ \implies log_{5}(3x + 5) = \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x) }$

and now since the logs have common bases

$\mathsf{ \implies \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x) }$

we're left with

$\mathsf{ \implies 3x + 5 = 1 - 3x}$

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8 0

3 years ago

Task number 3 on this attachment is what i need help with

Anni [7]

So $49.95+$1.19(384)+(384/18)($3.89) = $589.896
Idk if you need to round your answer.

4 0

3 years ago