3 years ago

What are the solutions to the system of linear equations graphed below?

Mathematics

1 answer:

amid [387]3 years ago

5 0

Answer:

Graph on the left:

(-4,-7) & (3,0)

Graph on the right:

(-4,7) & (4,9)

Step-by-step explanation:

Look for when the intersect

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see below

Step-by-step explanation:

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$(-2^2)^{-6}\div(2^{-5})^{-4}=2^{-12}\div2^{20}=2^{-12-20}=\boxed{2^{-32}}\\\\2^4\cdot(2^2)^{-2}=2^{4+2(-2)}=2^0=\boxed{1}\\\\(2^2)^2\cdot (2^3)^{-3}=2^{2(2)+3(-3)}=2^{4-9}= \boxed{2^{-5}}\\\\(-2^{-4})^{-2}\cdot(2^2)^0=2^{(-4)(-2)}\cdot 1= \boxed{2^8}$

Please note that ...

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