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barxatty [35]
3 years ago
14

Given figure A and figure B such that ar (A) = 20 sq. units and ar (B) = 20 sq. units. A. Figure A and B are congruent B. Figure

A and B are not congruent C. Figure A and B may or may not be congruent D. Figure A and B are similar
Mathematics
1 answer:
sladkih [1.3K]3 years ago
8 0
Option C. the figures may or may not be congruent.. a square with area as 20 sq is not congruent with any random shape with 20 sq unit as the area ..
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Paul makes 3 5/6 dozen cookies. He gives each of his friends 1/6 dozen cookies.
AveGali [126]
If he gives ALL of the cookies away..

3 5/6 = 6/6 + 6/6 + 6/6 + 5/6

6+6+6+5 = 23

Paul has 23 friends. (if he takes 1/6, then he has 22)

hope this helps
7 0
3 years ago
1.75x+1.25y=2<br> 7x+5y=9<br> how many solutions does this system of equations have?
Vlad1618 [11]

Answer:

true 7x+5y=9

Step-by-step explanation:

7 0
3 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
3 years ago
What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}

      b = base length = 25 mm

       H = height

         We have to find 'H' using Pythagorean theorem,

              slant height (hypotenuse) = 28 mm

                                                  leg₁ = base length  ÷ 2 = 25÷2 = 12.5

                                                  leg₂ = H

     H² + (12.5)² = 28²

                  H²   = 784 - 156.25

                         = 627.75

                   \sf H = \sqrt{627.75}

                 H = 25.01 mm

          \sf  \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }

                                                     = 5229 mm³

                                                     

       

\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}

3 0
2 years ago
Read 2 more answers
Please help with this question.
Rzqust [24]
(cos Ф -cos Ф)² + (cos Ф + cos Ф)²

Firstly: (cos Ф -cos Ф)² = 0² = 0

Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф

Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф

4 0
3 years ago
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