Given
Sofia cuts a piece in the shape of a kite for an art project
top two sides measure 20 cm each
bottom two sides measure 13 cm each.
One diagonal, EG, measures 24 cm
Find out the length of the other diagonal, DF.
To proof
As given in the question and also shown in the diagram shown below
DE = EF = 20cm
DG = GF = 13cm
EG = 24cm
DF = ?
In kite shape
One diagonal is the perpendicular bisector of the other diagonal.
i.e EG is the perpendicular bisector of DF
i.e EG is divided into two equal parts
thus EA = AG = 12cm
in Δ EAF
By applying the pythagorus theorem
we have
EF² = FA²+ EA²
20² = 12² + FA²
400 -144 = FA²
256 =FA²
![\sqrt{256} =FA](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%3DFA)
16cm = FA
Now in Δ DAG
DG² = AG² + DA²
13² = 12 ²+ DA²
169 -144 = DA²
25 = DA²
![\sqrt{25} =DA](https://tex.z-dn.net/?f=%5Csqrt%7B25%7D%20%3DDA)
5cm = DA
Thus diagonal DF = DA + FA
= 5 + 16
= 21cm
Hence proved