Part (a)
<h3>Answer:
2(2.4+w) = 14.2</h3>
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Explanation:
L = 2.4 = length
W = unknown width
The perimeter of any rectangle is P = 2(L+W)
We replace L with 2.4, and replace P with 14.2 to get 14.2 = 2(2.4+w) which is equivalent to 2(2.4+w) = 14.2
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Part (b)
<h3>Answer:
w = 4.7</h3>
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Explanation:
We'll solve the equation we set up in part (a)
2(2.4+w) = 14.2
2(2.4)+2(w) = 14.2
4.8+2w = 14.2
2w = 14.2-4.8
2w = 9.4
w = 9.4/2
w = 4.7
The width must be 4.7 cm.
<span>1. Which ratios form a proportion?
a. 4/5, 20/25 -----> 4/5, 4/5 Yes
b.8/12, 18/24 -----> 2/3, 3/4 No
c. 1/3, 7/24 ------> 8/24,7/24 No
d. 2/5, 6/16</span> -----> 2/5, 3/8 No
<span>2.Which ratio forms a proportion with 9/15 = 3/5
a.3/6 = 2/3 No
b.2/3 No
c.12/30 = 2/5 No
d. 6/10</span> = 3/5 Yes
<span>3.Which proportion has cross products of 5 x 24 and 8x15?
a. 5/8=15/24 ----> 5 * 24 = 8 * 15 Yes
b.5/24=8/15 ----> 5 * 15 = 8 * 24 No
c.8/24=15/5 ----> 5 * 8 = 15 * 24 No
d. 15/8=5/24
</span>----> 15 * 24 = 5 * 8 No
Answer:
- Total surface area of cylinderal can is 150.8 cm²
<u>Step-by-step </u><u>explanation</u><u>:</u><u> </u>
Given that a cylinderal can has base with a diameter of 6 cm and its height measures 5 cm.
So,
Radius = Diameter/2 = 6/2 = 3 cm
We know that,
- TSA of cylinder = 2πr(h + r)
Substituting required values:
➝ TSA = 2 × 22/7 × 3(5 + 3)
➝ TSA = 44/ 7 × 3 × 8
➝ TSA = 1056/7
➝ TSA = 150.8 cm²
Hence,
- <u>Total </u><u>surface </u><u>area </u><u>of </u><u>cylinderal</u><u> </u><u>can </u><u>is </u><u>1</u><u>5</u><u>0</u><u>.</u><u>8</u><u> </u><u>cm²</u>