6
8
6
2
hope it helps i think that is answer
Answer: i'm pretty sure it's option A
Answer:
so for what I'm thinking is 2*5 for the amount of hours in a school week and then you get 10 then times that by 15 for the amount of weeks in a semester which is 150 then times that by 3 and you get 450 thats the simple way so if you are also studying over the weekend it would be 630 of a entire year
Step-by-step explanation in the answer
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
a = -86.
Step-by-step explanation:
By the Factor Theorem, if x + 4 is a factor then P(-4) = 0, so:
P(-4) = 2(-4)^3 - 11(-4)^2 + a(-4)- 40 = 0
-128 - 176 - 4a - 40 = 0
-4a = 128 +176 + 40
-4a = 344
a = -86.
