Answer: 16x^2 - 9x + 11
Step-by-step explanation:
(5x^2+8x+18)+(11x^2-17x-7)
5x^2+8x+18+11x^2-17x-7
16x^2 - 9x + 11
Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
If two figures or lengths are similar, then the ratios of the corresponding lengths are equal.
Thus, 8/32 =5/x
8x = 160
x = 20 feet
Therefore, the length of the flag pole was 20 feet long
Length of AC is 5 I hope this helps I can’t think right right now so bare with me
Answer:
I would go with the first one
Step-by-step explanation:
I put 4/3 x 3.14 x 6² on the calculator and it gave me 150.72 so A is the closest I'm not 100% sure but ye