Answer:
150° and 210°
Step-by-step explanation:
1) according to the condition the required cosine is <0, it means the required angles are in the II-d and III-d quaters (see the attached picture no. 1);
2) it is known, that arccos(√3/2)=30°- the angle is between 0° and 90°, - but the requred angles are between 90° and 270° (see the picture no. 2), then
3) (angle)₁=180°-arccos(√3/2) and (angle)₂=180°+arccos(√3/2), then finally
(angle)₁=180°-30°=150°; (angle)₂=180°+30°=210°.
PS. note, the suggested way is not the only one.
Answer:
See below
Step-by-step explanation:
Okay so...I might be interpreting the question wrong-if I am please comment! I'll fix it to the best of my ability.
A) Plug in -5 to all x values
f(-5)=10(-5)-3
==50-3
f(-5)= -53
B) f(0)=10(0)-3
f(0)= -3
C) f(7)=10(7)-3
=70-3
f(7)=67
D) f(t^2+2)=10(t^2+2)-3
=10t^2+20-3
f(t^2+2)=10t^2+17
E) f(12-x)=10(12-x)-3
=120-10x-3
f(12-x)=117-10x
F) f(x+h)=10(x+h)-3
=10x+10h-3
14,800=60x+16y
x+y=441
that implies y=441-x so
14,800=60x+16(441-x)
14,800=60x+16*441-16x
14,800-16*441=44x
7744=44x
x=176 kids and 441-176 adults
The coefficient of the squared expression is 1/9
<h3>How to determine the coefficient of the squared expression?</h3>
A parabola is represented as:
y = a(x - h)^2 + k
Where:
Vertex = (h,k)
From the question, we have:
(h,k) = (-2,-3)
(x,y) = (-5,-2)
So, the equation becomes
-2 = a(-5 + 2)^2 - 3
Add 3 to both sides
1 = a(-5 + 2)^2
Evaluate the sum
1 = a(-3)^2
This gives
1 = 9a
Divide both sides by 9
a = 1/9
Hence, the coefficient of the squared expression is 1/9
Read more about parabolas at:
brainly.com/question/4061870
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