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2 years ago

Point T is on line segment SU. Given ST=2x+6, TU=4, and SU=4x, determine the numerical length of ST.

Mathematics

1 answer:

serg [7]2 years ago

3 0

The numerical length of ST is 16

<h3>How to determine the numerical length of ST?</h3>

The given parameters are:

ST = 2x + 6

TU = 4

SU = 4x

The above parameters can be represented as:

SU = ST + TU

This gives

4x = 2x + 6 + 4

Evaluate the like terms

2x = 10

Divide by 2

x= 5

Substitute x= 5 in ST = 2x + 6

ST = 2 * 5 + 6

Evaluate

ST = 16

Hence, the numerical length of ST is 16

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Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a

larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

$y_1=-4$

$x_2=4$

$y_2=12$

$m=3$

$n=1$

$[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]$

$[x=\frac{12-8}{4},y=\frac{36-4}{4}]$

$[x=\frac{4}{4},y=\frac{32}{4}]$

$[x=1,y=8]$

Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

7 0

3 years ago

in one month darius spends 10 hours walking dogs. How many dogs walks does he do in one month ALSO this is dividing a whole numb

MA_775_DIABLO [31]

Step-by-step explanation:

let's assume one month is 30 days you would multiply 10 by 30.

$10 \times 30 = 300$

which would be 300 hours in 1 month

now if one month is 31 days you would simply multiply 10 by 31.

$10 \times 31 = 310$

which would be 310 hours

6 0

3 years ago

Jim Tree has $3,300 in cash and $3,300 in owners equity. The following transactions take place. You withdraw $500 for yourself,

nirvana33 [79]

3,300-500=2,800
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8 0

3 years ago

Read 2 more answers

The number sentence 4×7=(4×3)+( 4×4) is an example of what property?

zlopas [31]

Answer:

Assicative property

Step-by-step explanation:

Hope this helped!

4 0

2 years ago

A random sample of 85 group leaders, supervisors, and similar personnel at General Motors revealed that, on average, they spent

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

From the information given,

Number of personnel sampled, n = 85

Mean or average = 6.5

Standard deviation of the sample = 1.7

We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.

For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.

z×standard deviation/√n

= 1.96 × 6.5/√85

= 1.38

The confidence interval for the mean number of years spent before promotion is

The lower end of the interval is 6.5 - 1.38 = 5.12 years

The upper end is 6.5 + 1.38 = 7.88 years

Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years

4 0

2 years ago