Point T is on line segment SU. Given ST=2x+6, TU=4, and SU=4x, determine the numerical length of ST.
1 answer:
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Answer:
Option C. 3√3
Step-by-step explanation:
Please see attached photo for brief explanation.
In the attached photo, we obtained the following:
Opposite = a
Adjacent = 3
Hypothenus = 6
Angle θ = 60°
We can obtain the value of 'a' as follow:
Tan θ = Opposite /Adjacent
Tan 60° = a/3
Cross multiply
a = 3 x Tan 60°
But: Tan 60° = √3
a = 3 x Tan 60°
a = 3 x √3
a = 3√3
Therefore, the length of the altitude of the equilateral triangle is 3√3.
