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stich3 [128]
3 years ago
13

find the x-intercepts of the parabola with vertex(6,27) and y-intercept (0,-81). write answer in form (x1,y1)(x2,y2). if necessa

ry ,round to the nearest hundredth .
Mathematics
2 answers:
sergey [27]3 years ago
7 0
The vertex form of the equation is:
y = a ( x - h )² + k
- 81 = a ( 0 - 6 )² + 27
- 81 = 36 a + 27
- 108 = 36 a
a = - 108 : 36
a = - 3
y = - 3 ( x - 6 )² + 27
y = - 3 ( x² - 12 x + 36 ) + 27
y = - 3 x² + 36 x - 108 + 27
y = - 3 x² + 36 x - 81
y = - 3 ( x² - 12 x + 27 )
x² - 12 x + 27 = 0
x² - 9 x - 3 x + 27 = 0
x ( x - 9 ) - 3 ( x - 9 ) = 0
( x - 9 ) ( x - 3 ) = 0
x 1 = 3,  x 2 = 9
Answer:
The x-intercepts are ( 3, 0 ) and ( 9, 0 ).
Simora [160]3 years ago
6 0

Answer:

(8.33) , (236.67)

Step-by-step explanation:

This is correct

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2 years ago
Jason has 20 coins composed of nickels and dimes. If the total value is $1.10 how many coins of each does he have
SOVA2 [1]

Answer:

Jason has 10 dimes and 2 nickels

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6 0
3 years ago
A ball is thrown upward from 3 feet iff the ground at an initial velocity of 64 feet per second. What is the maximum height the
Elza [17]

I found h max = 64 feet

Explanation: Ok...probably you can do this differently but I would try to find the vertex of the parabola describing the trajectory: 1) derive it: h ` ( t ) = 64 − 32 t 2) set derivative equal to zero: 64 − 32 t = 0 t = 64 32 = 2 sec 3) use this value of t into your trajectory: h ( 2 ) = h max 64 ⋅ 2 − 16 ⋅ 4 = 64 feet .

               

7 0
3 years ago
Easy Points...Must Answer question though!
Xelga [282]

Answer:

me. Its pretty sad consdering its been really helpful, and its been a great community. It was a safe space, but it had a few faults. not a problem, and we got great memes from there.

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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