Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
So?
-756*x +x =1 ?
-755 x = 1
x= -1/755
or
what two numbers when multiplied equal -756 but when added together equal 1?
numbers are x and y
x*y= -756
x+y=1
rearrange the 2nd eq
y=1-x
substitute
x(1-x)=-756
distribute
x-x^2=-756
solve for zero
x^2-x-756=0
factor/quadratic equation
Answer: raise 2 to the number of days, and then multiply this value by 3.
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
Firstly, find the value of f(3)
⇒ 
[sub in 3]
⇒ 
[multiply by 2 and add 1]
Now, find g(f(3))
⇒ 
[sub in 7]
⇒ 
[multiply by 3 and subtract 1]
⇒ 
[divide by 2]
Always try putting x=1 and x=-1 to see if we can find a zero.
If x=1 we get 5+8+1-2 which is not zero.
If we change the signs of the odd powers of x we get -5+8-1-2 which is zero so x=-1 is a zero and x+1 must therefore be a factor. Now we can use synthetic division to find the quadratic:
-1 | 5 8 1 -2
5 -5 -3 2
————
5 3 -2 | 0 = 5x²+3x-2 = (5x-2)(x+1).
Therefore the real zeroes are -1, 2/5, since -1 is a duplicate zero (because the cubic factorises into (5x-2)(x+1)²).
