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scoundrel [369]
3 years ago
7

Nick can purchase each milkshake for $2. For the first milkshake purchased Nick is willing to pay $4, for the second milkshake $

3, for the third milkshake $2 and for the fourth milkshake $1. What is the value of Nick's consumer surplus for the milkshakes he buys?
Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

The value of Nick's consumer surplus for the milkshakes he buys is $3.

Step-by-step explanation:

Given : Nick can purchase each milkshake for $2. For the first milkshake purchased Nick is willing to pay $4, for the second milkshake $3, for the third milkshake $2 and for the fourth milkshake $1.

To find : What is the value of Nick's consumer surplus for the milkshakes he buys?

Solution :

Nick can purchase each milkshake for $2.

For 1st milkshake purchased Nick is willing to pay $4

Consume surplus $4-$2=$2

For 2nd milkshake purchased Nick is willing to pay $3

Consume surplus $3-$2=$1

For 3rd milkshake purchased Nick is willing to pay $2

Consume surplus $2-$2=$0

For 4th milkshake purchased Nick is willing to pay $1

Consume surplus $1-$2=$-1 cannot be consider.

We add together the surplus from the 1st, 2nd, 3rd, and 4th milkshake

i.e. $2+$1+$0=$3

Therefore, the value of Nick's consumer surplus for the milkshakes he buys is $3.

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Answer:

17/12 = 1 5/12

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In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence
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The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

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(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

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b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

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