Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:
2 dozens, $41
Step-by-step explanation:
Given data
Man Street Florist charges
$18 for a dozen roses and a
$5 delivery fee
let the number of dozens be x
and the total charge for x dozens be y
hence
y= 18x+5--------------1
Blooms and Bouquets
charges $20 for a
dozen roses and a $1
delivery fee.
let the number of dozens be x
and the total charge for x dozens be y
hence
y= 20x+1 -------------2
Equate 1 and 2 we have
18x+5=20x+1
20x-18x= 5-1
2x= 4
x= 4/2
x= 2
Hence the number of dozens is 2
the cost is (put x= 2 in eqn 1 or 2)
y= 20(2)+1
y= 40+1
y= $41
Answer:
20,160
Step-by-step explanation:
The answer for the first slot is Alternate Interior Angles Theorem
Angle B and angle G are inside the "train tracks" formed by AB and GH. They are on opposite sides of the transversal line BG.
Along a similar line of reasoning, the answer for the second slot is Alternate Exterior Angles Theorem
The two parallel lines in question are AC and FH. The transversal line is FC. Angles ACB and HFG are on the exterior of the "train tracks" formed by the parallel lines.
The answer is C. They are intersecting
