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ivolga24 [154]
3 years ago
12

Use the Pythagorean theorem to find b. b, 13, 12 b =

Mathematics
2 answers:
Nana76 [90]3 years ago
4 0

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=\stackrel{adjacent}{12}\\ b=opposite\\ \end{cases} \\\\\\ \sqrt{13^2-12^2}=b\implies \sqrt{25}=b\implies 5=b

liubo4ka [24]3 years ago
4 0

Answer:

5

Step-by-step explanation:

a^2 + b^2 = c^2

13 is the hypotenuse because it is the longest side.

12^2 + b^2 = 13^2

144 + b^2 = 169

subtract the 144 from both sides to isolate the variable you are solving for

b^2 = 25

Square root both sides to solve

b = 5

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8 0
3 years ago
The variable y is directly proportional to the variable x. If y = 32 when x = 20, what is the value of x when y = 40?
elena55 [62]

Answer:

The Correct option is C ) 25

Therefore the value of x is 25 when y =40.

Step-by-step explanation:

Given:

Variable 'y' is directly proportional to the variable 'x'.

\therefore y=kx     ......Direct Variation

Where,

k = Constant of proportionality

To Find:

value of x = ? when y = 40

Solution:

First we need to find Constant of proportionality

When x = 20 and y = 32

Substituting the values we get

32=k\times 20\\k=\dfrac{32}{20}=1.6\\\\k=1.6

Now when k =1.6 , y = 40 then x will be

40=1.6\times x\\\\x=\dfrac{40}{1.6}=25\\\\x=25

Therefore the value of x is 25 when y =40.

6 0
3 years ago
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
Natalija [7]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
                      Determining the amplitude, midline, and period 

The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
                            Determining the type of function to use 

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x)1 sin   (\dfrac{1}{3}x) +5  = Solution
8 0
3 years ago
Find the diameter(s) of circle O.
schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

BC^2=r^2+r^2=2r^2

Thus we have

2r^2=(6\sqrt{2})^2

2r^2=72

r^2=36

r=6

The diameter of the circle O is D=2(6) = 12 units

5 0
3 years ago
Anyone know the answer to this?
ludmilkaskok [199]

Answer: 95 degrees :)

3 0
3 years ago
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