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emmainna [20.7K]
3 years ago
13

How do I do this question? Find the area of the patio below

Mathematics
2 answers:
Alina [70]3 years ago
4 0
The area of trapezoids is a=1/2h(b1+b2)
So: a=1/2 19 45(25+22 1/2)
MAXImum [283]3 years ago
4 0
 The answer is 940 1/2 by first you will have to add the length soo...
22 1/2 +25 is 47 1/2
But then you will have to 47 1/2 and  19 4/5  into a mixed number..
47 1/2 = 95/2
19 4/5 = 99/5
Then you multiply 95/2 and 99/5 and get 9405/10.After that then you will divide 9405 by 10 and you should get 940.5 which is also equal to 940 1/2 ft

Hopes this helps! <span>( ͡° ͜ʖ ͡°)</span>
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PLEASEEE HELP ME WHAT IS THE ANSWER!!
blagie [28]

Answer:

Number 3 is correct.

129.19m

Step-by-step explanation:

You might be wondering how did I got 32⁰, well, that's because they are alternate angles.

Now, we're trying to find the opposite side of the triangle.

Using the laws,

we got cos32⁰=x/243.8

243.8cos32⁰=x

129.19⁰

Mark me as Brian list?

3 0
3 years ago
Explain how you know 7/12 is greater than 1/3 but less than 2/3
Roman55 [17]
7/12
1/3=4/12
2/3=8/12

7/12>1/3
<span>7/12<2/3
</span>

convert all of these to a common denominator:
7/12 , 1/3 , 2/3
---
7/12 = 7/12
1/3 = 4/12
2/3 = 8/12
---
place into compound inequality:
---
(1/3=4/12) < (7/12=7/12) < (2/3=8/12)


3 0
3 years ago
Read 2 more answers
Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d
Olegator [25]

Answer:

The speed of the cars is 32 \frac{km}{h}

Step-by-step explanation:

First we must first have the clear concept that speed=\frac{distance}{time} or s=\frac{d}{t}

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: s_{1}=s+1 , t_{1}=2 and d_{1}= d_{2}

Car 1: s_{2}=s-10 , t_{2}=3 and d_{1}= d_{2}

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

d_{1}=s_{1}*t_{1}

d_{1}=(s+1)*2

d_{1}=2s+2

<em>Car 2</em>

d_{2}=s_{2}*t_{2}

d_{2}=(s-10)*3

d_{2}=3s.30

d_{1}=d_{2}

2s+2=3s-30

2+30=3s-2s

32=s

The speed of the cars is 32 km/hr

7 0
3 years ago
Captain has $30 flame has a $20 note $5 notes . how much more moneny does captain have
SCORPION-xisa [38]

Captain has $30 money

Flame has $20 +$5 =$25

difference =30-25=5

Captain has $5 more money

5 0
3 years ago
A family has two cars. the first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of
marusya05 [52]
Car 1 consumes 30 gallons of gas.Car 2 consumes 20 gallons of gas.
7 0
3 years ago
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