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V125BC [204]
3 years ago
8

On Monday 172 students went on a trip to the zoo all 4 buses were filled and 9 students had to travel in cars.How many students

were in each bus
Mathematics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

Three was 43 students in each bus

Step-by-step explanation:

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Name two examples of quadrilaterals,
kolezko [41]

Answer:

square and rectangle

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Hya think of a number "m" . She square it, add "y" to the answer and then subtract 7 from it. The final answer is "A". 1) Derive
Bond [772]
<h2><u>Solution (1)</u> :</h2>

Given, to find A we have to :

  • square m
  • Add y to m²
  • Subtract 7 from m² + y

From the question, the following equation can be formed :

=\tt  A = {m}^{2}   + y - 7

Therefore, the formula for finding A = m² + y - 7

<h2><u>Solution (2)</u> :</h2>

The value of A we can derive from the formula is :

=\tt A =  {m}^{2}  + y - 7

Value of m = 3 (given)

Which means :

=\tt A =   {3}^{2}  + y  - 7

=\tt \: A = 9 + y - 7

=\tt A = 9 - 7 + y

\color{plum} =\tt A = 2 + y

Thus, the value of A = 2+y

Therefore, the value of A = <u>2+y</u>

7 0
2 years ago
Evaluate (solve) the power: 2^9
german

Answer:

The corrext answer is, 512.

3 0
3 years ago
Read 2 more answers
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
Someone help plz!!!
rewona [7]
20 I think good luck
4 0
3 years ago
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