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PSYCHO15rus [73]
3 years ago
15

What is the equation of a line parallel to the line y = 4x - 5 with a y intercept of 3?*

Mathematics
1 answer:
victus00 [196]3 years ago
3 0
Y=4x +3 bc the slope needs to be the same just different y intercepts
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spencer spent 4 hours doing chores over the weekend. If he spent 2/3 for an hour on each chore, how many chores did he do.
Elina [12.6K]
2/3 + 2/3 + 2/3 + 2/3
8/3
2 2/3
4 0
3 years ago
Divide <br><br> (3x^2 + 9x + 7) divide by (x+2)
scZoUnD [109]

Answer:

The remainder is: 3x+3

The quotient is: 1

Step-by-step explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.

3 0
3 years ago
Read 2 more answers
an initial population of 5 squirrels increases by 9% each year for 10 years.using x for years and y for the number of squirrels,
ivann1987 [24]

Answer:

Equation: y(1.09)^x

After 10 years there will be about 12 squirrels.

Step-by-step explanation:

y(1.09)^x

=5(1.09)^10

=(approx.) 12 squirrels

5 0
3 years ago
Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
When multiplying two polynomials of degrees m and n, will the product be a polynomial? If so, explain, and state the degree.
vfiekz [6]
Yes.
The degree will be m+n
7 0
3 years ago
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