√200 = √2·100 = √2 · √100 = 10√2
Given: 48 students took the exam.
A total of 18 + 10 = 28 students scored 80% or above.
To find the percentage, take the part (28 students) divided by the whole (48 students) then multiply the quotient by 100.
(28 students / 48 students) x 100 = 58.33%
58.33% of the students who took the exam scored an 80% or higher
Given :-
- Two triangles with their two angles equal .
To Find :-
Answer :-
Here in ∆ABC and ∆EDC ,
CAB =
CED (given )-
CBA =
CDE (given)
Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,
→ AC/EC = BC/DC
→ AC/9 = 8/12
→ AC = 8/12 * 9
→ AC = 6
<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>
I hope this helps.
Answer:
√7 ≈ 2.646
Step-by-step explanation:
The law of cosines is applicable. It tells you ...
c² = a² + b² - 2ab·cos(C) . . . . . where a, b, c are triangle side lengths, and angle C is opposite side c.
Filling in the given information, you have ...
c² = 2² + 3² - 2·2·3·cos(60°) = 4 + 9 - 12·(1/2) = 7
c = √7 ≈ 2.646
The length of the third side is √7, about 2.646 units.
Answer:
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Step-by-step explanation:
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