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2 years ago

Helpppppppppppppppppppppppppppppppppppppppppppp

Mathematics

2 answers:

Anestetic [448]2 years ago

7 0

1.-36

2.-22.06

3.-42.1

You welcome :)

Vesna [10]2 years ago

7 0

1. 36
2. -22.06
3. -15.5

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A train traveled 325 miles in 5 hours. What was the train's average rate of speed in miles per hour?

Nostrana [21]

65 miles per hour

325/5= 65

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2 years ago

Read 2 more answers

Sophie pays m dollars to rent a car for the weekend on the drive home she buys $45 worth of gasoline her friend melody pays for

Hoochie [10]

Complete Question

Sophie pays m dollars to rent a car for the weekend. On the drive home, she buys $45 worth of gasoline. Her friend Melody pays for one-half the cost of the car rental only. Write an expression you could use to determine how much Sophie spent.

Answer:

1/2m + 45

Step-by-step explanation:

We are told in the question that:

On the drive home, she buys $45 worth of gasoline.

Her friend Melody pays for one-half the cost of the car rental only.

Sophie pays m dollars to rent a car for the weekend.

The amount sophie pays for car rental = m - 1/2m

= 1/2m

Therefore, the expression used to determine how much sophie spent is written as:

1/2 × $m + $45

1/2m + 45

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3 years ago

a rectangle has an area of 34 sqaure feet. A larger rectangle has an area of 124 sqaure feet. what is the percent increase of th

amid [387]

Answer:

<u>The difference in areas:</u>

124 - 34 = 90 square feet

<u>Percent increase:</u>

90/34*100% = 264.71%

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2 years ago

Determine whether the ratios are equivalent. 3:8 and 9: 24. are they equivalent or not?

Simora [160]

Answer:

Yes, they are equivalent.

Step-by-step explanation:

9 / 3 = 3

24 / 3 = 8

3:8 is just the simplified version of 9:24. This is due to 9:24 being divided by three, becoming 3:8.

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2 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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2 years ago