Answer :
To answer the question above, we need to know the rules of arithmetic operations in algebra. The same variable only can be operated with the same variable for example, if 2x + 3x then the result is 5x, but 2x + 3y cannot be 5xy because the variable is different. To answer the question we need to know the value of r and s. Now, check the question, what is the result of the equation 3r = 10 + 5s, when r = 10?.
To find out the value of s, the value of r is known so we just include it to the equation.
r = 10 then 3r = 3 . (10) = 30
3r = 10 + 5s
30 = 10 + 5s
(because there are 2 Constanta and 1 variable, we must change the place and the value of 1 Constanta to operate them)
30 = 10 + 5s
30 - 10 = 5s
(10 changed to -10 because it moves to the other side of the equal sign)
20 = 5s
(to find out the value of s or a variable, we need to divide Constanta with coeffitient in remaining)
20/5 = s
4 = s, so the value of s is 4
now we finish the first equation which is 3r = 10 + 5s, we just include the value of the variable then finish it.
3r = 10 + 5s
3 . (10) = 10 + 5 . (4)
30 = 10 + 20
30 = 30
because they have the same result, it means the value of variables was right. so the final result of the question is 30.
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Answer Details
Subject: Mathematics
Chapter: Algebra
Grade: Secondary School
Keyword: How do you find and X in an equation?, What does the X mean in an equation?, How do you work out the value of x?