(CHALLENGE QUESTION FOR ALL OF YOU):
2 answers:
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<u>Answer:</u>
Both Sally ans Manny can detail a car in 20.6 min.
<u>Solution: </u>
Let us assume that together they will take total x minutes to detail the car.
Sally detail the car in 50 min.
So in 1 min sally can detail \left(\frac{1}{50}\right) of the car.
Hence in x min sally can detail \left(\frac{x}{50}\right) of the car.
Manny can detail a car in 35 min.
So in 1 min many can detail \left(\frac{1}{35}\right) of the car.
Hence in x min Manny can detail \left(\frac{x}{35}\right) of the car.
So we can say,
\left(\frac{x}{50}\right)+\left(\frac{x}{35}\right)=1
x\left(\frac{1}{50}+\frac{1}{35}\right)=1
x\left(\frac{7+10}{350}\right)=1
\left(\frac{17 x}{350}\right)=1
x=\left(\frac{350}{17}\right)=20.5
8 20.6
So, both of them can detail a car in 20.6 min.
Answer:
Step-by-step explanation:
Hello!
The variables of interest are:
X₁: Number of cases of polio observed in kids that received the placebo vaccine.
n₁= 201299 total children studied
x₁= 110 cases observed
X₂: Number of cases of polio observed in kids that received the experimental vaccine.
n₂= 200745 total children studied
x₂= 33 cases observed
These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂
You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁
a)
H₀: p₂ = p₁
H₁: p₂ ≠ p₁
α: 0.05
Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005
Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002
Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004
This test is two-tailed, using the critical value approach, you have to determine two critical values:
Then if ≤ -1.96 or if
≥ 1.96, the decision is to reject the null hypothesis.
If -1.96 < < 1.96, the decision is to not reject the null hypothesis.
⇒ = -4.76, the decision is to reject the null hypothesis.
b)
H₀: p₂ = p₁
H₁: p₂ ≠ p₁
α: 0.01
The value of = -4.76 doesn't change, since we are working with the same samples.
The only thing that changes alongside with the level of significance is the rejection region:
Then if ≤ -2.576or if
≥ 2.576, the decision is to reject the null hypothesis.
If -2.576< < 2.576, the decision is to not reject the null hypothesis.
⇒ = -4.76, the decision is to reject the null hypothesis.
c)
Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.
Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)
I hope this helps!