ASAP PLEASE !!!!!!The area of the figure is _________.

Mathematics

2 answers:

Anarel [89]3 years ago

7 0

Answer:

the answer is 459.2 inches

lutik1710 [3]3 years ago

5 0

Answer:

392 in²

Step-by-step explanation:

Separate it into a rectangle and a triangle by "drawing" a line where it begins to slant downwards. You get a rectangle with a 16in width and a 19in height. The area of this is 304 in². The triangle measures 16in width and 11 in height (30-19). To calculate the area of a triangle, multiply height and width and 0.5. This gives an area of 88. The add the areas together.

88+304=392 in²

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Two angles are supplementary one angle measure 12 more than the other find the measures

Furkat [3]

We have a + b = 180 and a = 12 + b;
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12 + 2b = 180;
2b = 168;
b = 84;
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5 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,