Question

The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y.

Answer 1

Given: The wavelength of radio wave is x and frequency is y.

Here, frequency (y) = 3.0×10⁹ Hz

And the velocity of the radio wave which is equal to the velocity of light (v) =  3.0×10⁸ m/s

Since, wavelength and frequency is inversely proportional to each other then

        x ∝ (1/y)

or,      x = v /y  ----------------(1)

Here, v is the proportionality constant.

Now, we shall substitute the given values of y and v in equation (1),

                               x =   (3.0×10⁸ m/s) ÷ (3.0×10⁹ Hz)

or,                            x =  0.1 m

Hence, the required wavelength of the radio wave will be 0.1 m.

Answer 2

The relationship between wavelength and frequency is expressed by the equation λν=c where λ is the wavelength, v is the frequency and c is the speed of light which has a value of 3x10^8 m/s.

 λν=c
 λ(3 × 10^9)= 3x10^8
 λ = 0.1 m

Hope this answers the question.