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2 years ago

What is the area of the trapezoid?

Mathematics

2 answers:

EastWind [94]2 years ago

7 0

Answer:

37.5 square units

Step-by-step explanation:

A=a+b/2h => 5 + 10 / 2 x 5

lorasvet [3.4K]2 years ago

4 0

Answer:

37.5 square units

Step-by-step explanation:

In the picture the square units is 50.

Minus and turn into a trapezoid and is 37.5 square units.

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A simple random sample of 20 days in which Parsnip ate seeds was selected, and the mean amount of time it took him to eat the se

bearhunter [10]

Answer:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

Step-by-step explanation:

We know the following info from the problem

$\bar X_1 = 14.5$ sample mean for the group 1

$s_1 = 3.98$ the standard deviation for the group 1

$n_1= 20$ the sample size for group 1

$\bar X_2 = 13.9$ sample mean for the group 2

$s_1 = 4.03$ the standard deviation for the group 2

$n_2= 17$ the sample size for group 2

We have all the conditions satisifed since we have random samples.

We want to construct a confidence interval for the true difference of means and the correct formula for this case is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given :

$df = n_1 +n_2- 2 = 20+17-2=35$

The confidence level is 0.9 or 90% and the significance level is $\alpha=1-0.9=0.1$ and $\alpha/2 = 0.05$ and the critical value for this case is:

$t_{\alpha/2} = 1.69$

And replacing the info given we got:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

5 0

2 years ago

What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ?

Alina [70]

Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)

slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7

a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)

2nd one

5 0

2 years ago

Can Someone Help. ?

Elanso [62]

Answer:

Step-by-step explanation:

I think its 6 times greater because the length was tripled and the width was doubled thus : 3 * 2 = 6

HOPE THIS HELPED

8 0

2 years ago

What are the solutions of the quadratic equation 4x^2-8x-12=0

Wewaii [24]

Answer:

Step-by-step explanation:

$4x^2-8x-12=0\\{}\qquad\qquad^{\div4\qquad\div4}\\x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\\\\x+1=0\quad\vee\quad x-3=0\\\\x=-1\quad\vee\quad x=3$

6 0

3 years ago

What is the value of x in the triangle?

Ksivusya [100]

Answer:

X = 102

Step-by-step explanation:

41 + 37 + x = 180

78 + x = 180

X = 180 - 78 = 102

7 0

2 years ago