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Gekata [30.6K]
3 years ago
5

An angle measures 79.4 degrees more than the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

The angles are: 50.3 and 129.7

Step-by-step explanation:

The sum of supplementary angles is 180°.

Let x be one angle then the other angle will be x+79.4

Using the supplementary angle sum

x+x+79.4 = 180\\2x+79.4 = 180\\2x = 180-79.4\\2x = 100.6\\\frac{2x}{2} = \frac{100.6}{2}\\x = 50.3

For the measurement of 2nd angle

x+79.4 => 50.3+79.4 => 129.7

Hence,

The angles are: 50.3 and 129.7

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The product of two consecutive odd integers is 72. Write a quadratic equation to find the integers,
zimovet [89]

<u>Answer:</u>

x^2 + x - 72 = 0

<u>Explanation:</u>

We are given product of two consecutive odd integers is equal to 72.

Let one integer be x , then since these are consecutive and odd so the other integer will be equal to x + 1.  

Their product is equal to 72. So,

x * (x + 1) = 72

=> x^2 + x = 72

=>  x^2 + x - 72 = 0 is the required quadratic equation.

5 0
3 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
How many units of a 10% solution are needed to prepare 500 units of a 2% solution?
Akimi4 [234]
First find how many units of solution there is:

500* 2% = 500(.02) = 10 units

You need 10 units of solution in 'x' units of a 10% solution.

x*10% = 0.1x = 10 units   ----->  x = 10/0.1 = 100

100 units are needed
8 0
3 years ago
Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4
fomenos

Answer:

  x g(x)

  1 −10

  2 −12

  3 −14

Step-by-step explanation:

Substitute the values and do the arithmetic.

Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.

  f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic

 g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice

6 0
3 years ago
a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur
ser-zykov [4K]

Answer:

36

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

\frac{4 \times 3}{2}  = 6

Area of rectangle is length x width so the area is

7 \times 6 = 42

Subtract 6 from 42.

42 - 6 = 36

3 0
3 years ago
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