Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
0.018 will be 18/1000 = 9/500
Ok don’t worry this is a very easy topic
It falls under “gradients of a straight line”
I’ll try my best to explain the question but u can find plenty of videos online (Fuse School or Cognito) explaining the topic in detail.
Gradient means slope or how steep a line is.
To find the gradient we use the formula
(Change in y) / (change in x)
*Step 1*
Choose any two coordinates (exact) of the line from the graph
For line 1 let’s take
(2,4) (-3,4)
Now from this
the change in y= (4-4) = 0
the change in x = (-3-2) = -5
So the gradient = 0/-5 = 0
*Now this makes sense because a straight horizontal line has no slope and thus has a gradient of zero. So even without all the calculation we can figure this out easily.
Now for line 2 let’s take the coordinates:
(-3,1) (-3,3)
The change in y= (3-1) = 2
The change in x = (-3- -3) = 0
So gradient = 2/0 = “Undefined”
*The gradient of vertical straight line is always undefined (no gradient)*
*The gradient of horizontal straight lines is always 0*
Hope this helped and best of luck for your exams!
To make it easier, I am going to simplify it.
4×16-16 ? 4×[24-2×(4+8)]
64-16 ? 4×[24-2×12]
48 ? 4×[24-24]
48 ? 4×[0]
48 ? 4×0
48 ? 0
48>0
The symbol is >, so the answer is A.
