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RUDIKE [14]
3 years ago
8

Brendan has 33 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 615 cents, how many

dimes and how many quarters does he have?
Mathematics
1 answer:
Amanda [17]3 years ago
6 0
If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.

Brendan has 14 dimes and 19 quarters.
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A manufacturing facility is responsible for producing two components that are produced at states 1 (poor), 2 (below average), 3
garik1379 [7]

Answer:

a) i) P( final product is acceptable ) = 3/5

   ii) P ( final product not acceptable ) =  2/5

B)  P (  final product is acceptable | X =2 ) = 2/5

C)  P ( Y = 3 | Final product is acceptable ) = 2/5

Step-by-step explanation:

Given data :

5 states : 1 (poor), 2 (below average), 3 (average), 4 (good), and 5 (excellent)

Number of components produced = 2

X ( component 1 ) ∴ P(X) = 1/5

Y ( component 2 ) ∴ P(Y) = 1/5

Aim : Sum of Final product needs to be ≥ 6

<u>A) Probability of a final product been acceptable and also unacceptable</u>

P( final product is acceptable ) ; P(X + Y ≥ 6 )

= 1/5 ∑ P( Y ≥ 6 - x )

= 1/5 ( P( Y ≥ 5 ) + P( Y ≥ 4 ) + P( Y ≥ 3 ) + P( Y ≥ 2 ) + P( Y ≥ 1 )

= 1/5 ( 1/5 + 2/5 + 3/5 +4/5 + 1 )

= 3/5

P ( final product not acceptable ) = 1 - 3/5 = 2/5

B) P (  final product is acceptable | X =2 )

 ∴ P ( Y ≥ 4 )

   = 2/5

C) P ( Y = 3 | Final product is acceptable )

∴ P ( X ≥ 3 ) ≠ P( Y ≥ 3 )  ( because they are not independent )

  = 1 - 3/5 = 2/5.

8 0
3 years ago
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