The displaced volume of the water, because of the submersion of the object, is equal to the volume of the object.
So to find the volume of the object we calculate the difference in volume of water:
33.1-25.1 = 8 ml
Since 1 mL of water has the volume of 1cm^3, then the volume of the object is 8 cm^3.
The density of the object is found by the formula:
density= mass/volume= (3 g) / (8 cm^3) = 3/8 (g/cm^3)= 0.375 g/cm^3
Answer: 0.375 g/cm^3
The LCM of 6 and 4, is 12.
Answer:
A. Z = 2 + N13
Step-by-step explanation:
Let's solve your equation step-by-step.
0=z2+4z−9
Step 1: Subtract z^2+4z-9 from both sides.
0−(z2+4z−9)=z2+4z−9−(z2+4z−9)
−z2−4z+9=0
For this equation: a=-1, b=-4, c=9
−1z2+−4z+9=0
Step 2: Use quadratic formula with a=-1, b=-4, c=9.
z=
−b±√b2−4ac
2a
z=
−(−4)±√(−4)2−4(−1)(9)
2(−1)
z=
4±√52
−2
z=−2−√13 or z=−2+√13
Answer:
The answer for the first equation is,
B. 11
The answer for the second equation is,
D.none of these.
Answer:
The correct answer is option D. 13
Step-by-step explanation:
From the figure we can see two matrices A and B
<u>To find the sum of a₃₂ and b₃₂</u>
From the given attached figure we get
a₃₂ means that the third row second column element in the matrix A
b₃₂ means that the third row second column element in the matrix B
a₃₂ = 4 and b₃₂ = 9
a₃₂ + b₃₂ = 4 + 9
= 13
The correct answer is option D. 13
