So you have 5 sides you can add 2/5+2/5+2/5+2/5+2/5 = 10/5 = 2 miles around the park. Or you can multiply 5 sides (pentagon) times each side of 2/5 mile thus..... 5*2/5 = 10/5 = 2 so this is also 2 miles around the perimeter.
Answer:
21
Step-by-step explanation:
we know that according to the isosceles triangle theorem, that the angles of the triangle are 90, 2x+3, 2x+3
from the triangle angle sum theorem, we know that 4x+6 = 90
solving, we get 4x=84, x=21
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
6x^10 − 96x^2
Factor out 6x^2
6x^2 ( x^8 - 16)
Notice that inside the parentheses we have the difference of squares
6x^2 ( x^4 ^2 - 4^2) a^2 - b^2 = (a-b) (a+b)
6x^2 ( x^4 -4) (x^4 +4)
Notice that x^4-4 is also the difference of squares
6x^2 ( x^2^2 -2^2) (x^4 +4)
6x^2 ( x^2 -2) ( x^2 +2) (x^4 +4)
Note also that x^4 + 4 can be factored into (x^2+2x+2)(x^2-2x+2)
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
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