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2 years ago

What lessons learned from 2008 cam we apply to today's current situation

Mathematics

1 answer:

Nikolay [14]2 years ago

6 0

Answer:

Listen!

Good communication starts with listening closely and asking lots of questions. Understand what is happening. Understand what people (coworkers, customers, etc.) are feeling and confronting. Care about what they are feeling and confronting, because it is their reality. Listen before you speak, and certainly listen before you make decisions.

Be as clear as possible.

If you have listened well and understand what others are facing, you will be better able to communicate clearly because you will be answering questions before they are asked. Through the year+ of running Treasury’s HFA Initiative, we held countless webinars with large numbers of participants. This was a primary method of group communication. We spent a great deal of time preparing for those.

Anticipate and plan.

Even if you are getting pressed from every side, you need to take time to think, anticipate and plan. Anticipate plausible scenarios and plan for those scenarios. Manage toward what you want to achieve, but also plan for other plausible scenarios and be prepared. If you have leadership responsibility, others are expecting you to be prepared.

Have resolve and navigate.

Know that you will face a series of challenges and resolve that you will navigate through those challenges. If you’ve taken the time to think and plan for scenarios, you will be better prepared to navigate through whatever comes your way.

Find ways to recharge even if the pressure seems relentless.

You need to find some way to disengage, even for short periods of time, to recharge the batteries and get perspective. Meditate, pray, take a walk… whatever works for you. Energy is finite.

Keep the end in sight.

When you feel overwhelmed, know that these challenges will pass. Do your best… listen, think, plan, navigate, and push through. In the end, you will be stronger than you were when the challenge started.

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David drove 580 km on 7 hour journey. on the city roads he drove 60km/h and on the he drove 100km/h. How long did he drive at ea

serious [3.7K]

Answer:

3 hours on the city roads and 4 hours on the other roads

Step-by-step explanation:

580 (total miles driven) - 400 (4 hours of driving 100km/h) = 180 (miles left)

180 (miles left to drive) / 60 (km/h) = 3 (hours driven at the speed of 60km/h)

I hope this helps :)

5 0

2 years ago

Solve for the given time.

LenaWriter [7]

Answer:

8851.86

Step-by-step explanation:

100-4.3= 95.7%

15000(.957)^12

5 0

2 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

4 months ago

Your car gets 30 miles per gallon of gasoline. if you drive your car at 45 miles per hour, how much gasoline do you use in an ho

Xelga [282]

Answer:

1.5

Step-by-step explanation:

45 divided by 30 = 1.5

Hope this helps

8 0

2 years ago

Alex is working to simplify

stich3 [128]

Answer:

is this all?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What lessons learned from 2008 cam we apply to today's current situation​

What lessons learned from 2008 cam we apply to today's current situation