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3 years ago

- 2a + 5b - 3c + 2a + b

Mathematics

2 answers:

kifflom [539]3 years ago

6 0

The answer would be 6b-3c because a would cancel out and be 0

Svet_ta [14]3 years ago

6 0

(-2a+2a)=0
(5b+b)=6b
6b-3c

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I need help with numbers 1 and 2

Snowcat [4.5K]

Answer:

1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.

2.Since the polynomial can be factored, it is not prime.

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3 years ago

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Answers:
(x+2) = 55 degrees

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the given is 72 degrees

Explanation:
A triangle always equals 180 degrees. It was given that one of the angle measures is 72 degrees. 180-72=108. Now I need to find the value of x. (x+2)+x=108. Solving this equation I get x=53. Substitute this back into the angle measures and u get the answers as stated above.

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3 years ago

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5^12/5^6 Is the correct response. When equal numbers with different exponents are divided then the you must subtract the exponents.
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3 years ago

Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

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Combine like terms

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Now find (a + b)²

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Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

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2 years ago

Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$