p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
∠ 2 = 75° , ∠ 1 = 105°
Step-by-step explanation:
∠ 2 and 75° are alternate angles and are congruent , then
∠ 2 = 75°
∠ 1 and ∠ 2 are a linear pair and sum to 180° , that is
∠ 1 + ∠ 2 = 180°
∠ 1 + 75° = 180° ( subtract 75° from both sides )
∠ 1 = 105°