Answer:
3x²+(-27x) +0
Step-by-step explanation:
The given expression is :
x + 3x² – 28x
We need to solve this in the form of ax²+bx+c.
we can write the given expression as :
3x²-28x+x = 3x²-27x
= 3x²+(-27x) +0
If we compare the given expression with the general expression, we find that,
a = 3, b = -27 and c = 0
Hence, the required equation is 3x²+(-27x) +0.
Domain: all real numbers
Range: y>-3
The rule for quotients of similar bases with different exponents is:
(a^c)/(a^b)=a^(c-b) in this case:
15^18/(15^3)=15^15
